Python 3.14 (Coding): Remove Element Test

The solution approach of the problem is to initializing two pointers, i and j, both pointing to the first element of the array. We iterate through the array using the i pointer until it reaches the end of the array. For each element at nums[i], we perform the following checks: a. If the value at nums[i] is not equal to the given value val, it means we want to keep this element in the modified array. In this case, we assign the value at nums[i] to the position nums[j] in the array and increment j by 1. This effectively moves the valid elements to the beginning of the array. b. If the value at nums[i] is equal to val, it means we want to remove this element from the array. In this case, we simply skip it and don't increment j. This ensures that j remains pointing to the next available position where a valid element can be placed. c. After processing each element, we increment i by 1 to move on to the next element in the array. Once the iteration is complete, we return the value of j. This value represents the new length of the modified array, as all the valid elements have been moved to the first j positions.