Merge k Sorted Lists Test

Upcoming Test

The goal of the problem is to merge two k sorted list into one single sorted list.

Available in

  • English

Summarize this test and see how it helps assess top talent with:

2 Skills measured

  • Linked List
  • Two pointers

Test Type

Coding Test

Duration

30 mins

Level

Intermediate

Questions

1

Use of Merge k Sorted Lists Test

The solution approach is to take a reference to a vector of ListNode pointers lists as input and returns a pointer to the head of the merged linked list. The function first checks the size of the lists vector. If it is empty, it returns nullptr since there are no linked lists to merge. If there is only one linked list in the vector, it directly returns that list since it is already sorted. The function creates two new vectors of ListNode pointers, lists1 and lists2. lists1 contains the first half of the linked lists from the lists vector, and lists2 contains the second half. This splitting is done by copying the appropriate elements from lists using vector slicing. The function recursively calls mergeKLists on lists1 and lists2 to merge the two halves of the linked lists and obtain two merged sorted linked lists l1 and l2. If l1 is nullptr, it means there were no linked lists in lists1 or the merged result of lists1 is empty. In this case, the function directly returns l2 since it represents the merged result. The variable ret is initialized to l1, which will be used to store the head of the merged result. The function enters a while loop that runs as long as l2 is not nullptr. This loop is responsible for merging the two sorted linked lists l1 and l2. Inside the loop, there is an if statement that checks if the value of the current node in l1 is greater than the value of the current node in l2. If it is, the values of the two nodes are swapped so that l1 always contains the smaller value. There is another while loop nested inside the outer while loop. This nested loop finds the correct position to insert the current node of l2 into l1. It iterates as long as l1->next is not nullptr and the value of l1->next is less than the value of the current node in l2. This loop moves l1 forward until it finds the correct position. Once the correct position is found, the next pointer of the current node in l2 is updated to point to l1->next, and the next pointer of l1 is updated to point to the current node in l2. This effectively inserts the current node of l2 into the correct position in the merged list. After the insertion, the next node of l2 is stored in a temporary variable tmp2 and l2 is updated to point to the next node. This step is performed to continue the merging process for the remaining nodes in l2. Once the while loop finishes, the merged result is stored in ret, which contains the head of the merged list. Finally, the function returns ret, which represents the head of the merged linked list.

Skills measured

In the Merge k Sorted Lists problem, the Linked List skill is crucial for efficiently merging multiple sorted lists into a single sorted list. Linked Lists allow for easy traversal and manipulation of elements, making it easier to merge the lists in the correct order. Understanding Linked Lists is important for understanding how to properly merge the lists while maintaining their sorted order. This skill is essential for solving problems that involve manipulating and merging multiple lists in an efficient manner.

The two pointers skill in Merge k Sorted Lists involves using two pointers to iterate through the linked lists simultaneously and merge them in sorted order. This skill is important because it allows us to efficiently compare and merge multiple sorted lists without using extra space for storing all elements. By keeping track of two pointers, we can easily determine the smallest element in each list and append it to the merged list in the correct order. This approach helps reduce time complexity and improve overall performance of the merging process.

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Subject Matter Expert Test

The Merge k Sorted Lists Subject Matter Expert

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